Optimal. Leaf size=221 \[ -\frac{9 b^2 \sin \left (3 a-\frac{3 b c}{d}\right ) \text{CosIntegral}\left (\frac{3 b c}{d}+3 b x\right )}{8 d^3}-\frac{b^2 \sin \left (a-\frac{b c}{d}\right ) \text{CosIntegral}\left (\frac{b c}{d}+b x\right )}{8 d^3}-\frac{b^2 \cos \left (a-\frac{b c}{d}\right ) \text{Si}\left (\frac{b c}{d}+b x\right )}{8 d^3}-\frac{9 b^2 \cos \left (3 a-\frac{3 b c}{d}\right ) \text{Si}\left (\frac{3 b c}{d}+3 b x\right )}{8 d^3}-\frac{b \cos (a+b x)}{8 d^2 (c+d x)}-\frac{3 b \cos (3 a+3 b x)}{8 d^2 (c+d x)}-\frac{\sin (a+b x)}{8 d (c+d x)^2}-\frac{\sin (3 a+3 b x)}{8 d (c+d x)^2} \]
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Rubi [A] time = 0.324418, antiderivative size = 221, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 5, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.227, Rules used = {4406, 3297, 3303, 3299, 3302} \[ -\frac{9 b^2 \sin \left (3 a-\frac{3 b c}{d}\right ) \text{CosIntegral}\left (\frac{3 b c}{d}+3 b x\right )}{8 d^3}-\frac{b^2 \sin \left (a-\frac{b c}{d}\right ) \text{CosIntegral}\left (\frac{b c}{d}+b x\right )}{8 d^3}-\frac{b^2 \cos \left (a-\frac{b c}{d}\right ) \text{Si}\left (\frac{b c}{d}+b x\right )}{8 d^3}-\frac{9 b^2 \cos \left (3 a-\frac{3 b c}{d}\right ) \text{Si}\left (\frac{3 b c}{d}+3 b x\right )}{8 d^3}-\frac{b \cos (a+b x)}{8 d^2 (c+d x)}-\frac{3 b \cos (3 a+3 b x)}{8 d^2 (c+d x)}-\frac{\sin (a+b x)}{8 d (c+d x)^2}-\frac{\sin (3 a+3 b x)}{8 d (c+d x)^2} \]
Antiderivative was successfully verified.
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Rule 4406
Rule 3297
Rule 3303
Rule 3299
Rule 3302
Rubi steps
\begin{align*} \int \frac{\cos ^2(a+b x) \sin (a+b x)}{(c+d x)^3} \, dx &=\int \left (\frac{\sin (a+b x)}{4 (c+d x)^3}+\frac{\sin (3 a+3 b x)}{4 (c+d x)^3}\right ) \, dx\\ &=\frac{1}{4} \int \frac{\sin (a+b x)}{(c+d x)^3} \, dx+\frac{1}{4} \int \frac{\sin (3 a+3 b x)}{(c+d x)^3} \, dx\\ &=-\frac{\sin (a+b x)}{8 d (c+d x)^2}-\frac{\sin (3 a+3 b x)}{8 d (c+d x)^2}+\frac{b \int \frac{\cos (a+b x)}{(c+d x)^2} \, dx}{8 d}+\frac{(3 b) \int \frac{\cos (3 a+3 b x)}{(c+d x)^2} \, dx}{8 d}\\ &=-\frac{b \cos (a+b x)}{8 d^2 (c+d x)}-\frac{3 b \cos (3 a+3 b x)}{8 d^2 (c+d x)}-\frac{\sin (a+b x)}{8 d (c+d x)^2}-\frac{\sin (3 a+3 b x)}{8 d (c+d x)^2}-\frac{b^2 \int \frac{\sin (a+b x)}{c+d x} \, dx}{8 d^2}-\frac{\left (9 b^2\right ) \int \frac{\sin (3 a+3 b x)}{c+d x} \, dx}{8 d^2}\\ &=-\frac{b \cos (a+b x)}{8 d^2 (c+d x)}-\frac{3 b \cos (3 a+3 b x)}{8 d^2 (c+d x)}-\frac{\sin (a+b x)}{8 d (c+d x)^2}-\frac{\sin (3 a+3 b x)}{8 d (c+d x)^2}-\frac{\left (9 b^2 \cos \left (3 a-\frac{3 b c}{d}\right )\right ) \int \frac{\sin \left (\frac{3 b c}{d}+3 b x\right )}{c+d x} \, dx}{8 d^2}-\frac{\left (b^2 \cos \left (a-\frac{b c}{d}\right )\right ) \int \frac{\sin \left (\frac{b c}{d}+b x\right )}{c+d x} \, dx}{8 d^2}-\frac{\left (9 b^2 \sin \left (3 a-\frac{3 b c}{d}\right )\right ) \int \frac{\cos \left (\frac{3 b c}{d}+3 b x\right )}{c+d x} \, dx}{8 d^2}-\frac{\left (b^2 \sin \left (a-\frac{b c}{d}\right )\right ) \int \frac{\cos \left (\frac{b c}{d}+b x\right )}{c+d x} \, dx}{8 d^2}\\ &=-\frac{b \cos (a+b x)}{8 d^2 (c+d x)}-\frac{3 b \cos (3 a+3 b x)}{8 d^2 (c+d x)}-\frac{9 b^2 \text{Ci}\left (\frac{3 b c}{d}+3 b x\right ) \sin \left (3 a-\frac{3 b c}{d}\right )}{8 d^3}-\frac{b^2 \text{Ci}\left (\frac{b c}{d}+b x\right ) \sin \left (a-\frac{b c}{d}\right )}{8 d^3}-\frac{\sin (a+b x)}{8 d (c+d x)^2}-\frac{\sin (3 a+3 b x)}{8 d (c+d x)^2}-\frac{b^2 \cos \left (a-\frac{b c}{d}\right ) \text{Si}\left (\frac{b c}{d}+b x\right )}{8 d^3}-\frac{9 b^2 \cos \left (3 a-\frac{3 b c}{d}\right ) \text{Si}\left (\frac{3 b c}{d}+3 b x\right )}{8 d^3}\\ \end{align*}
Mathematica [A] time = 2.6147, size = 181, normalized size = 0.82 \[ -\frac{9 b^2 \sin \left (3 a-\frac{3 b c}{d}\right ) \text{CosIntegral}\left (\frac{3 b (c+d x)}{d}\right )+b^2 \sin \left (a-\frac{b c}{d}\right ) \text{CosIntegral}\left (b \left (\frac{c}{d}+x\right )\right )+b^2 \cos \left (a-\frac{b c}{d}\right ) \text{Si}\left (b \left (\frac{c}{d}+x\right )\right )+9 b^2 \cos \left (3 a-\frac{3 b c}{d}\right ) \text{Si}\left (\frac{3 b (c+d x)}{d}\right )+\frac{d (b (c+d x) \cos (a+b x)+d \sin (a+b x))}{(c+d x)^2}+\frac{d (3 b (c+d x) \cos (3 (a+b x))+d \sin (3 (a+b x)))}{(c+d x)^2}}{8 d^3} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.02, size = 313, normalized size = 1.4 \begin{align*}{\frac{1}{b} \left ({\frac{{b}^{3}}{12} \left ( -{\frac{3\,\sin \left ( 3\,bx+3\,a \right ) }{2\, \left ( \left ( bx+a \right ) d-ad+bc \right ) ^{2}d}}+{\frac{3}{2\,d} \left ( -3\,{\frac{\cos \left ( 3\,bx+3\,a \right ) }{ \left ( \left ( bx+a \right ) d-ad+bc \right ) d}}-3\,{\frac{1}{d} \left ( 3\,{\frac{1}{d}{\it Si} \left ( 3\,bx+3\,a+3\,{\frac{-ad+bc}{d}} \right ) \cos \left ( 3\,{\frac{-ad+bc}{d}} \right ) }-3\,{\frac{1}{d}{\it Ci} \left ( 3\,bx+3\,a+3\,{\frac{-ad+bc}{d}} \right ) \sin \left ( 3\,{\frac{-ad+bc}{d}} \right ) } \right ) } \right ) } \right ) }+{\frac{{b}^{3}}{4} \left ( -{\frac{\sin \left ( bx+a \right ) }{2\, \left ( \left ( bx+a \right ) d-ad+bc \right ) ^{2}d}}+{\frac{1}{2\,d} \left ( -{\frac{\cos \left ( bx+a \right ) }{ \left ( \left ( bx+a \right ) d-ad+bc \right ) d}}-{\frac{1}{d} \left ({\frac{1}{d}{\it Si} \left ( bx+a+{\frac{-ad+bc}{d}} \right ) \cos \left ({\frac{-ad+bc}{d}} \right ) }-{\frac{1}{d}{\it Ci} \left ( bx+a+{\frac{-ad+bc}{d}} \right ) \sin \left ({\frac{-ad+bc}{d}} \right ) } \right ) } \right ) } \right ) } \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [C] time = 2.17134, size = 452, normalized size = 2.05 \begin{align*} -\frac{b^{3}{\left (i \, E_{3}\left (\frac{i \, b c + i \,{\left (b x + a\right )} d - i \, a d}{d}\right ) - i \, E_{3}\left (-\frac{i \, b c + i \,{\left (b x + a\right )} d - i \, a d}{d}\right )\right )} \cos \left (-\frac{b c - a d}{d}\right ) + b^{3}{\left (i \, E_{3}\left (\frac{3 i \, b c + 3 i \,{\left (b x + a\right )} d - 3 i \, a d}{d}\right ) - i \, E_{3}\left (-\frac{3 i \, b c + 3 i \,{\left (b x + a\right )} d - 3 i \, a d}{d}\right )\right )} \cos \left (-\frac{3 \,{\left (b c - a d\right )}}{d}\right ) + b^{3}{\left (E_{3}\left (\frac{i \, b c + i \,{\left (b x + a\right )} d - i \, a d}{d}\right ) + E_{3}\left (-\frac{i \, b c + i \,{\left (b x + a\right )} d - i \, a d}{d}\right )\right )} \sin \left (-\frac{b c - a d}{d}\right ) + b^{3}{\left (E_{3}\left (\frac{3 i \, b c + 3 i \,{\left (b x + a\right )} d - 3 i \, a d}{d}\right ) + E_{3}\left (-\frac{3 i \, b c + 3 i \,{\left (b x + a\right )} d - 3 i \, a d}{d}\right )\right )} \sin \left (-\frac{3 \,{\left (b c - a d\right )}}{d}\right )}{8 \,{\left (b^{2} c^{2} d - 2 \, a b c d^{2} +{\left (b x + a\right )}^{2} d^{3} + a^{2} d^{3} + 2 \,{\left (b c d^{2} - a d^{3}\right )}{\left (b x + a\right )}\right )} b} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.589684, size = 907, normalized size = 4.1 \begin{align*} -\frac{8 \, d^{2} \cos \left (b x + a\right )^{2} \sin \left (b x + a\right ) + 24 \,{\left (b d^{2} x + b c d\right )} \cos \left (b x + a\right )^{3} + 18 \,{\left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x + b^{2} c^{2}\right )} \cos \left (-\frac{3 \,{\left (b c - a d\right )}}{d}\right ) \operatorname{Si}\left (\frac{3 \,{\left (b d x + b c\right )}}{d}\right ) + 2 \,{\left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x + b^{2} c^{2}\right )} \cos \left (-\frac{b c - a d}{d}\right ) \operatorname{Si}\left (\frac{b d x + b c}{d}\right ) - 16 \,{\left (b d^{2} x + b c d\right )} \cos \left (b x + a\right ) +{\left ({\left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x + b^{2} c^{2}\right )} \operatorname{Ci}\left (\frac{b d x + b c}{d}\right ) +{\left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x + b^{2} c^{2}\right )} \operatorname{Ci}\left (-\frac{b d x + b c}{d}\right )\right )} \sin \left (-\frac{b c - a d}{d}\right ) + 9 \,{\left ({\left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x + b^{2} c^{2}\right )} \operatorname{Ci}\left (\frac{3 \,{\left (b d x + b c\right )}}{d}\right ) +{\left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x + b^{2} c^{2}\right )} \operatorname{Ci}\left (-\frac{3 \,{\left (b d x + b c\right )}}{d}\right )\right )} \sin \left (-\frac{3 \,{\left (b c - a d\right )}}{d}\right )}{16 \,{\left (d^{5} x^{2} + 2 \, c d^{4} x + c^{2} d^{3}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sin{\left (a + b x \right )} \cos ^{2}{\left (a + b x \right )}}{\left (c + d x\right )^{3}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: NotImplementedError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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